The NFL announced today that New York Jets safety Jaiquawn Jarrett was named AFC Defensive Player of the Week.
DEFENSE: S JAIQUAWN JARRETT, NEW YORK JETS
· Jarrett posted two interceptions, a fumble recovery, 10 tackles and one sack in the Jets’ 20-13 win against Pittsburgh.
· His fumble recovery occurred deep inside Steelers’ territory and provided the Jets with possession at the 20-yard line in the first quarter. Five plays later, quarterback MICHAEL VICK threw a touchdown pass to rookie tight end JACE AMARO to give New York a 17-0 lead.
· Jarrett’s two interceptions were the first of his NFL career. He was part of a unit that helped limit Pittsburgh, which averaged 41.3 points per game in the three preceding contests, to 13 points.
· Jarrett is the first NFL player with two interceptions, a sack and a fumble recovery in the same game since CHARLES WOODSON on November 26, 2009 against Detroit.
· In his fourth season from Temple, this is Jarrett’s first career Player of the Week Award. He is the first Jet to win a Player of the Week Award this season.
· He is the first Jets safety to be named Defensive Player of the Week since 2006 (KERRY RHODES, Week 3).
